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Series Circuits Calculation Practice Test Questions Answers:
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Question 1 of 10
1. Question
1 pointsWhat will be the equivalent Resistance in the given Circuit:
Correct
In the Circuit Three Resistances are connected in series.
In Series Circuit Req = R1 + R2 + . . .+ Rn
Req = 10 + 10 + 10 = 30ΩAnswer: 30Ω
Incorrect
In the Circuit Three Resistances are connected in series.
In Series Circuit Req = R1 + R2 + . . .+ Rn
Req = 10 + 10 + 10 = 30ΩAnswer: 30Ω
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Question 2 of 10
2. Question
1 pointsCalculate the Current flowing through the Circuit:
Correct
Voltage in the Circuit = 5 + 5 = 10V
Resistance in the Circuit = 10 + 10 + 10 = 30 ohms
Current in the Circuit = (V/I) = (10/30) = 0.334 AAnswer: i = 0.334A
Incorrect
Voltage in the Circuit = 5 + 5 = 10V
Resistance in the Circuit = 10 + 10 + 10 = 30 ohms
Current in the Circuit = (V/I) = (10/30) = 0.334 AAnswer: i = 0.334A
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Question 3 of 10
3. Question
1 pointsWhat is the equivalent ICapacitance value of the Circuit:
Correct
The Capacitances are connected in parallel in the Circuit:
1/Ceq = 1/C1 + 1/C2 + … + 1/Cn
1/Ceq = 1/(2) + 1/(2) + 1/(2)
1/Ceq = 3/2
Ceq = 2/3Answer: 2/3 mF
Incorrect
The Capacitances are connected in parallel in the Circuit:
1/Ceq = 1/C1 + 1/C2 + … + 1/Cn
1/Ceq = 1/(2) + 1/(2) + 1/(2)
1/Ceq = 3/2
Ceq = 2/3Answer: 2/3 mF
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Question 4 of 10
4. Question
1 pointsCalculate the equivalent Inductance Value of the Circuit:
Correct
Inductors are Connected in Series
In a Series Circuit Leq = L1 + L2 + .. + Ln|
Leq = 2C + 2C + 2C = 6C mHAnswer: 6C mH
Incorrect
Inductors are Connected in Series
In a Series Circuit Leq = L1 + L2 + .. + Ln|
Leq = 2C + 2C + 2C = 6C mHAnswer: 6C mH
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Question 5 of 10
5. Question
1 pointsCalculate the Equivalent Capacitance value:
Correct
1/Ceq = 1/(1mF) + 1/(mF) + 1/(3 mF)
Ceq = 3/7 mFIncorrect
1/Ceq = 1/(1mF) + 1/(mF) + 1/(3 mF)
Ceq = 3/7 mF -
Question 6 of 10
6. Question
1 pointsCalculate the Voltage V in the given circuit:
Correct
Current flowing through the Circuit = 5 A
Voltage across 5Ω Resistor = I x R = 5A x 5Ω = 25Answer: 25V
Incorrect
Current flowing through the Circuit = 5 A
Voltage across 5Ω Resistor = I x R = 5A x 5Ω = 25Answer: 25V
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Question 7 of 10
7. Question
1 pointsIf the equivalent Resistance Value of the Circuit = 30Ω. What will the value of the unknown resistance:
Correct
Equivalent Resistance Value = 30Ω
Resistance of the Circuit = 10 + 5 + R which is equal to 30Ω
Therefore 15 + R = 30; R = 15ΩAnswer: 15Ω
Incorrect
Equivalent Resistance Value = 30Ω
Resistance of the Circuit = 10 + 5 + R which is equal to 30Ω
Therefore 15 + R = 30; R = 15ΩAnswer: 15Ω
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Question 8 of 10
8. Question
1 pointsFind the Value of Voltage V in the Circuit:
Correct
Supply Voltage in the Circuit = 50 V
Current flowing through the Circuit = 5 A
Equivalent Resistance of the Circuit = (V)/(I) = (50/5) = 10 Ω
Equivalent Resistance of the Circuit given = 2 + 2 + R = 10; R = 6 ΩVoltage across 6Ω resistor = I x R = 6 x 5 = 30 VAnswer: 30 V
Incorrect
Supply Voltage in the Circuit = 50 V
Current flowing through the Circuit = 5 A
Equivalent Resistance of the Circuit = (V)/(I) = (50/5) = 10 Ω
Equivalent Resistance of the Circuit given = 2 + 2 + R = 10; R = 6 ΩVoltage across 6Ω resistor = I x R = 6 x 5 = 30 VAnswer: 30 V
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Question 9 of 10
9. Question
1 pointsTwo Voltage sources V 1 and V 2 are connected in series as shown in the figure and equivalent voltage of the circuit is also given. What will be the condition:.
Correct
Incorrect
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Question 10 of 10
10. Question
1 pointsTwo Current Sources are Connected in series, what is the condition to connect the circuit:
Correct
Incorrect